OK, I'm confused about the effect of tire size on "effective" gear ratio. Please correct me where I'm wrong and explain what I'm not understanding.
My '90 Tracker is running 1:1 trans ratio in 3rd gear, 1:1 transfer case ratio in 2H, and the rear differential is 4.62:1, so my final drive ratio is 4.62:1, correct? That's because my pinion gear is turning 4.62 times for every ring rotation because the ring gear has 4.62 times the teeth of the pinion gear, yes?
Now, if I replace my 275/75-15 tires (27" diameter) with 30x9.5 (30" diameter), I will decrease the number of tire RPMs and associated engine RPMs at any given speed, right?
So, why does my "effective" drive ratio become 5.13:1? I would have thought that the "effective" ratio would have decreased given that my RPMs decreased. The pinion gear is still turning 4.62 times for every ring rotation.
Now I guess I would look at it that the ring is only turning 90% of a rotation for the 30" versus the 27" so my "effective" ratio would be 4.16:1 (lower number, higher gearing, lower RPM) , but maybe that's the wrong way to look at it. The ring and pinion have to turn 111% of what they did with 27" to get a full rotation at 30", which would mean even though the engine would turn slower they'd still have to make up the 11% difference to get a full rotation.
What I'm trying to tie this to is MPG. It would seem that if the engine RPMs for a given speed went down, MPG should go up. But, if the gear ratio were increased (from 4.62 to 5.13) then MPG would go down, which seems to be the effect most people observe when they switch to a bigger tire.
As you can see, I'm VERY
HELP!